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error question

If the error in measuring the sides of a cuboid is 3 %, what is the percentage error in the area of one face?

If the error in measuring the sides of a cuboid is 2 %, what is the percentage error in the volume of the cube?

Could somebody explain how to do this please?

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Original post by jacksonmeg
If the error in measuring the sides of a cuboid is 3 %, what is the percentage error in the area of one face?

If the error in measuring the sides of a cuboid is 2 %, what is the percentage error in the volume of the cube?

Could somebody explain how to do this please?


Assune a value for the true length of a side. If error in measuring is 3%, what will be the measured length?
Square this to get the measured area and compare with true area.
Ditto for volume.
Original post by jacksonmeg
If the error in measuring the sides of a cuboid is 3 %, what is the percentage error in the area of one face?

If the error in measuring the sides of a cuboid is 2 %, what is the percentage error in the volume of the cube?

Could somebody explain how to do this please?


Try with a number

100

Can be between 97 and 103

So what can the area be
Reply 3
Original post by TenOfThem
Try with a number

100

Can be between 97 and 103

So what can the area be

i've used 100
103*103 = 10609
100*100=10000
10000/10609 * 100 = 94.259, so would the error be 5.74%?
Original post by jacksonmeg
i've used 100
103*103 = 10609
100*100=10000
10000/10609 * 100 = 94.259, so would the error be 5.74%?


You might want to check the lower limit
Reply 5
Original post by TenOfThem
You might want to check the lower limit

ok
i've done 97*97=9409
100*100 = 10000
10000/9409*100 = 106.28
so the error would be 6.28?
would I have to take an average of the 2 or something?
(edited 9 years ago)
Original post by jacksonmeg
ok
i've done 97*97=9409
100*100 = 10000
10000/9409*100 = 106.28
so the error would be 6.28?
would I have to take an average of the 2 or something?


Depends what the question is

You do not want an average

You either want the maximum error or to say +one and -the other
Reply 7
Original post by TenOfThem
Depends what the question is

You do not want an average

You either want the maximum error or to say +one and -the other

add them? i can only give 1 answer so im not sure what to do
(edited 9 years ago)
Original post by jacksonmeg
add them? i can only give 1 answer so im not sure what to do


If you can only give one answer I would go for the maximum error
Reply 9
Original post by TenOfThem
If you can only give one answer I would go for the maximum error

bleh. it marked it wrong
Original post by jacksonmeg
bleh. it marked it wrong


Do you get another go
Original post by TenOfThem
Do you get another go

yup
Original post by jacksonmeg
yup


Maybe it just want 6.09

1.03 squared
Original post by TenOfThem
Maybe it just want 6.09

1.03 squared

6.09? where did you get that from?
Original post by jacksonmeg
6.09? where did you get that from?


1.03 squared, as I said
Original post by TenOfThem
1.03 squared, as I said

1.03*1.03 = 6.09?
Original post by jacksonmeg
1.03*1.03 = 6.09?


No
Original post by TenOfThem
No

doesn't want that either
Original post by jacksonmeg
doesn't want that either


Ok

New thought

Try the smaller one from before, it did not say plus or minus in the question so maybe you were only meant to try adding 3%
Original post by TenOfThem
Ok

New thought

Try the smaller one from before, it did not say plus or minus in the question so maybe you were only meant to try adding 3%

Doesn't want that either x_x

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