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Calculate the pH of H2SO4

0.150 moldm-3 H2SO4.

At which stage do I divide by 2?
Wouldn't you multiply the concentration by 2 to get the moles of H+ ions and then -log that?

So it would be 0.15 x 2 = 0.3
Then -log(0.3)
(edited 9 years ago)
Reply 2
Avatar for Lighfy
Lighfy
3
H2SO4 is a strong acid so fully dissociates, so you can assume that [H+] = [H2SO4]

Therefore pH = -log[0.150x2]
(edited 9 years ago)
Reply 3
Avatar for Pigster
Pigster
20
Just after you randomly multiply a number by two.

I don't see at any stage why you'd want to divide by two.

[H+] = [H2SO4] x 2
pH = -log[H+]
Original post by Damien_Dalgaard
0.150 moldm-3 H2SO4.

At which stage do I divide by 2?


You times the concentration by 2 then put that conc into the pH log equation thingy
H2SO4 is diprotic so you get twice the number of protons
Original post by Lighfy
H2SO4 is a strong acid so fully dissociates, so you can assume that [H+] = [H2SO4]

Therefore pH = -log[0.150x2]


You mean [H+] = 2[H2SO4] ?
Reply 7
Avatar for Lighfy
Lighfy
3
Original post by Gaiaphage
You mean [H+] = 2[H2SO4] ?


Yes, sorry :colondollar:

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