Matrix
How to find a matrix from a shape and how do you put it in this form
x'=-y
y'=x
x'=ax+cy
y'=bx+dy
Book says this
"The distance of the point (x,y) from the axis is y units the point (x.y) moves 2y units parallel to the x axis so is new position is (x+2y,y)
The transformation can be written as
x'=1x+2y
y'=0x +1y"
x'=-y
y'=x
x'=ax+cy
y'=bx+dy
Book says this
"The distance of the point (x,y) from the axis is y units the point (x.y) moves 2y units parallel to the x axis so is new position is (x+2y,y)
The transformation can be written as
x'=1x+2y
y'=0x +1y"
(edited 9 years ago)
Well this will do x'=y and y'=x. Having the 1s in the off diagonal swaps x and y and the - sign fixes the sign.
By the way, I couldn't suppress the return after the matrix, obviiously they are on the same line.
BTW, I did not find your question very clear. Do you want the abcd bit or the number bit in bold done? If you practice multiplying 2 by 2 matrices with a vector you will see the fairly simple patterns that emerge.
Unparseable latex formula:
\left( \begin{array}{cc}[br]0 & -1 \\[br]1 & 0 \end{array} \right)\[br] \left( \begin{array}{c}[br]x \\[br]y \end{array} \right)\][br]
By the way, I couldn't suppress the return after the matrix, obviiously they are on the same line.
BTW, I did not find your question very clear. Do you want the abcd bit or the number bit in bold done? If you practice multiplying 2 by 2 matrices with a vector you will see the fairly simple patterns that emerge.
(edited 9 years ago)
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