units with ln or log of a variable URGENT

Hi,
if i was doing an experiment and measured for example current for different batteries then took the natural log of each value for current what would the units be, would it still be amps or would it be ln(amps) or no units at all?
Thanks

AFAIK you can only take a log of a dimensionless number. The ln(amps) doesn't have any meaning. A similar case is if you had $e^{I}$ where I is current, that is also a dimensionless number as e^(anything) must be dimensionless.

I'm only taking A level though, so I could be wrong.

Thanks so does this mean it wouldnt have any units?

The definition of a natural logarithm is the power to which Eulers number (e) must be raised in order to equal the number in question.

i.e.

$e^x = 20$

ln(20) Amperes means

$x = 2.9957$

i.e.

$e^{2.9957} = 20$

the natural logarithm of 20 (2.9957) is dimensionless.

Therefore $20 \mathrm {\ Amps} = e^{2.9957} \mathrm {\ Amps}$

A bit confused, if i plotted a graph of the ln of a value against something else would the ln vairiable have a unit??

No. The axis would just be labelled as ln(I).

Thanks, are there any cases where there would be a unit?