Hey, I am doing the iodine clock method with the reaction between peroxodisulphate ions and iodide ions?
I need help with drawing out the reaction mechanism. I know that the iodide is oxidised by peroxodisulphate and I believe it goes in 3 steps:
1. S2O8 2- + 2I - --> IS2O8 3-
2. IS2O8 3- --> I+ + 2SO4 2-
3. I+ + I- --> I2
Thank you so much to anyone who helps!