A2 Chemistry calculation Question
Hi I can't seem to workout how to do this question. If we workout the moles of ethanedioate can we not just take it away from 1.10 g?
The NaOH titration will give you the number of mol of ethanedioic acid.
The manganate titration will give you the number of mol of ethanedoate AND ethanedioic acid. Subtracting one from the other will give you the number of mol of sodium ethanedoate.
Converting both amounts to masses will give you the mass (by subtraction) of the sand.
The manganate titration will give you the number of mol of ethanedoate AND ethanedioic acid. Subtracting one from the other will give you the number of mol of sodium ethanedoate.
Converting both amounts to masses will give you the mass (by subtraction) of the sand.
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