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C4 Integration by Parts

So yeah..

π2πx2sin(x2) dx\displaystyle\int^{2\pi}_{\pi}x^{2}sin(\frac{x}{2})\ dx

WolframAlpha says
8π28π168\pi^{2}-8\pi-16 :rolleyes:
(edited 9 years ago)
Reply 1
your F(π)F(\pi) should be:

(0+4(2π+0)) (0+4(2 \pi+0))

leading to the minus 8pi

(cos(pi/2)=0, sin(pi/2)=1)
(edited 9 years ago)
Reply 2
Original post by Hasufel
your F(π)F(\pi) should be:

(0+4(2π+0)) (0+4(2 \pi+0))

leading to the minus 8pi


Oops..

But how did I get 10π210\pi^{2} then, confused.. :rolleyes:

EDIT: Nevermind I found the problem. Thanks
(edited 9 years ago)

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