The Student Room Group

Maths A-Level - Trigonometry - C3

I have been doing a past paper and got onto the question:

- Express 8 sin θ 6 cos θ in the form Rsin(θ α), where R > 0 and 0◦ < α < 90◦
I done this to get 10sin(θ-36.9)

Then the following question asks:
Find the greatest possible value of 32 sin x 24 cos x (16 sin y 12 cos y)
as the angles x and y vary.
I rewrote this as 40sin(θ-36.9)-20sin(θ-36.9)

The answer is 60, but I just don't understand how to get this... I know max of sin graph is 1, and that there is a 40 and 20 in equation but why do you add them together? So confused, I can't visualise it.
Original post by Chenice
I have been doing a past paper and got onto the question:

- Express 8 sin θ 6 cos θ in the form Rsin(θ α), where R > 0 and 0◦ < α < 90◦
I done this to get 10sin(θ-36.9)

Then the following question asks:
Find the greatest possible value of 32 sin x 24 cos x (16 sin y 12 cos y)
as the angles x and y vary.
I rewrote this as 40sin(θ-36.9)-20sin(θ-36.9)

The answer is 60, but I just don't understand how to get this... I know max of sin graph is 1, and that there is a 40 and 20 in equation but why do you add them together? So confused, I can't visualise it.

There are two angles, not one. The expression should be 40sin(θ36.9)20sin(ϕ36.9)40\sin(\theta -36.9) -20\sin(\phi -36.9).
Maximising this, you know the maximum value of sinx is 1 and the minimum value is -1. The first term has a positive sign, so sin(θ36.9)\sin(\theta-36.9) should be maximised to maximise the expression. The second term has a negative sign, so sin(ϕ36.9)\sin(\phi-36.9) should be minimised to maximise the expression.
Hence you have 40 - 20(-1) = 40 + 20 = 60.

Quick Reply

Latest