Rates of Reactions and Orders help!
So I went over this topic again for revision purposes.
Why is the reaction 1st order wrt H+ and DIMP when as the conc of both doubles, the rate quadruples? :s
Question and MS are attached.
Any help appreciated!
Why is the reaction 1st order wrt H+ and DIMP when as the conc of both doubles, the rate quadruples? :s
Question and MS are attached.
Any help appreciated!
One way I thought about this is squaring the concentration and getting
0.01 and 0.04
then its the same ratio as the initial rate. so First order.
Is this right?
0.01 and 0.04
then its the same ratio as the initial rate. so First order.
Is this right?
There is information missing.
You can't know if it is 1st order WRT [H+] AND [DIMP] or 2nd order WRT [H+] or 2nd order WRT [DIMP].
Were you told / worked out earlier that it is 1st order WRT [DIMP]?
If you were, the table makes sense. Between expt. 1 & 2, the [DIMP] doubled, which would double the rate, but the rate has quadrupled, i.e. it has doubled, then something else has made the rate double. Oooh look, [H+] has also doubled. Hmmm, doubling [H+] leads to a doubling of the rate. That sounds familiar.
You can't know if it is 1st order WRT [H+] AND [DIMP] or 2nd order WRT [H+] or 2nd order WRT [DIMP].
Were you told / worked out earlier that it is 1st order WRT [DIMP]?
If you were, the table makes sense. Between expt. 1 & 2, the [DIMP] doubled, which would double the rate, but the rate has quadrupled, i.e. it has doubled, then something else has made the rate double. Oooh look, [H+] has also doubled. Hmmm, doubling [H+] leads to a doubling of the rate. That sounds familiar.
Original post by Pigster
There is information missing.
You can't know if it is 1st order WRT [H+] AND [DIMP] or 2nd order WRT [H+] or 2nd order WRT [DIMP].
Were you told / worked out earlier that it is 1st order WRT [DIMP]?
If you were, the table makes sense. Between expt. 1 & 2, the [DIMP] doubled, which would double the rate, but the rate has quadrupled, i.e. it has doubled, then something else has made the rate double. Oooh look, [H+] has also doubled. Hmmm, doubling [H+] leads to a doubling of the rate. That sounds familiar.
You can't know if it is 1st order WRT [H+] AND [DIMP] or 2nd order WRT [H+] or 2nd order WRT [DIMP].
Were you told / worked out earlier that it is 1st order WRT [DIMP]?
If you were, the table makes sense. Between expt. 1 & 2, the [DIMP] doubled, which would double the rate, but the rate has quadrupled, i.e. it has doubled, then something else has made the rate double. Oooh look, [H+] has also doubled. Hmmm, doubling [H+] leads to a doubling of the rate. That sounds familiar.
Yeah in previous parts I worked out that dimp is 1st order.
Original post by Pigster
There is information missing.
You can't know if it is 1st order WRT [H+] AND [DIMP] or 2nd order WRT [H+] or 2nd order WRT [DIMP].
Were you told / worked out earlier that it is 1st order WRT [DIMP]?
If you were, the table makes sense. Between expt. 1 & 2, the [DIMP] doubled, which would double the rate, but the rate has quadrupled, i.e. it has doubled, then something else has made the rate double. Oooh look, [H+] has also doubled. Hmmm, doubling [H+] leads to a doubling of the rate. That sounds familiar.
You can't know if it is 1st order WRT [H+] AND [DIMP] or 2nd order WRT [H+] or 2nd order WRT [DIMP].
Were you told / worked out earlier that it is 1st order WRT [DIMP]?
If you were, the table makes sense. Between expt. 1 & 2, the [DIMP] doubled, which would double the rate, but the rate has quadrupled, i.e. it has doubled, then something else has made the rate double. Oooh look, [H+] has also doubled. Hmmm, doubling [H+] leads to a doubling of the rate. That sounds familiar.
Thanks for the explanation, I get it now
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