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Given that the solution to
(2a^2-7a+6)/ (a^2-a-2) >=1
is
a <-1 or a >=4.
Deduce range of a for (2-7a+6a^2)/(1-a-2a^2) is more than or equal to 1.
(^ means to the power of.)
Reply 1
Original post by crystalong
Given that the solution to
(2a^2-7a+6)/ (a^2-a-2) >=1
is
a <-1 or a >=4.
Deduce range of a for (2-7a+6a^2)/(1-a-2a^2) is more than or equal to 1.
(^ means to the power of.)


Consider that the given solution is determined by the roots of polynomials
in the numerator and the denominator.

How change the roots of this polynomial when we change the quadratic term coefficient
with the constant term?
Reply 2
Original post by crystalong
Given that the solution to
(2a^2-7a+6)/ (a^2-a-2) >=1
is
a <-1 or a >=4.
Deduce range of a for (2-7a+6a^2)/(1-a-2a^2) is more than or equal to 1.
(^ means to the power of.)


This appears to be a duplicate of your other thread where you were given a suggestion for how to solve this.

Please do not duplicate threads unnecessarily :smile:

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