Hi, need some guidance if you don't mind.
Question.
In the B.E of (2k+x)^n where k is a constant and n is a positive integer, the co-efficient of x^2 is equal to the co-efficient of x^3.
PROVE that n = 6k+2!!
My answer so far using (a+b)^n
so
n(n-1)/2 * 2k^n-2 * x^2 = n(n-1)(n-2)/6 * 2k^n-2 * x^3
the answer in the booklet says the next step is...
2k = (n-2)/3
HOW does it go from my step the next step is where Im struggling?
Thanks