The Student Room Group

Complex numbers

:smile:
(edited 8 years ago)
Reply 1
draw a diagram to see where your number lies
Reply 2
Original post by TeeEm
draw a diagram to see where your number lies


cant do that
Reply 3
unable or you are not meant to?
Reply 4
Original post by TeeEm
unable or you are not meant to?

i can draw one
tbh i dont know im very lost at the moment
Reply 5
if z is in the 1st quadrant, argz =arctan Imz/Rez
if z is in the 2nd quadrant, argz =arctan Imz/Rez
if z is in the 3rd quadrant, argz =arctan Imz/Rez - π
if z is in the 4th quadrant, argz = arctanImz/Rez

(if z is on the axis 0, pi/2, pi, -pi/2, starting with the positive x axis going clockwise)
(edited 8 years ago)
This is what this particular complex number looks like on the complex plane:


If you can compute the value of α\alpha, then the argument will be given by πα\pi - \alpha as you want the angle from the positive half of the real axis.
(edited 9 years ago)
Reply 7
Original post by TeeEm
if z is in the 1st quadrant, argz = Imz/Rez
if z is in the 2nd quadrant, argz = Imz/Rez
if z is in the 3rd quadrant, argz = Imz/Rez - π
if z is in the 4th quadrant, argz = Imz/Rez

(if z is on the axis 0, pi/2, pi, -pi/2, starting with the positive x axis going clockwise)


that makes perfect sense :smile:
buuuuuuuuuuuuut could you say it in the dumbest way possible i want to write it in notes
thankyou :smile:)))))
Reply 8
if it helps write it...
That is how I teach it.
Reply 9
omg that is awesome, see i think i made a mistake because i did mine like



is there a reason why you drew yours like that?






Original post by brittanna
This is what this particular complex number looks like on the complex plane:

If you can compute the value of α\alpha, then the argument will be given by πα\pi - \alpha as you want the angle from the positive half of the real axis.
Original post by TeeEm
if it helps write it...
That is how I teach it.


thankyou :smile:
Reply 11
The argument is defined as the angle that is made with the positive real axis. So your angle is pi/2 radians too small!
The definition of argument is the angle between the complex number and the positive part of the real axis. The angle you've specified there is the one between the complex number and the imaginary axis.

Also, by definition, the argument is between π\pi and π-\pi, and so if the complex number was on the other side of the real axis, then the argument would be negative (you didn't make this mistake anywhere, I just thought it would be worth pointing out).
Original post by davros
The argument is defined as the angle that is made with the positive real axis. So your angle is pi/2 radians too small!

thankyou :smile:
oh wow, maybe i missed that i had no idea

thankyou very much

Original post by brittanna
The definition of argument is the angle between the complex number and the positive part of the real axis. The angle you've specified there is the one between the complex number and the imaginary axis.

Also, by definition, the argument is between π\pi and π-\pi, and so if the complex number was on the other side of the real axis, then the argument would be negative (you didn't make this mistake anywhere, I just thought it would be worth pointing out).
Reply 15
Original post by TeeEm
if z is in the 1st quadrant, argz = Imz/Rez
if z is in the 2nd quadrant, argz = Imz/Rez
if z is in the 3rd quadrant, argz = Imz/Rez - π
if z is in the 4th quadrant, argz = Imz/Rez

(if z is on the axis 0, pi/2, pi, -pi/2, starting with the positive x axis going clockwise)


Aren't those trigonometric ratios of the angle, not the angle.
Reply 16
Original post by RichE
Aren't those trigonometric ratios of the angle, not the angle.


:confused:
Reply 17
Original post by TeeEm
:confused:


You wrote, for example, argz = Imz/Rez.

So the argument of 1+i would be 1/1=1??

You mean tan(argz) = Imz/Rez.

So tan arg(1+i) = 1 meaning arg(1+i) = pi/4
Reply 18
Original post by RichE
You wrote, for example, argz = Imz/Rez.

So the argument of 1+i would be 1/1=1??

You mean tan(argz) = Imz/Rez.

So tan arg(1+i) = 1 meaning arg(1+i) = pi/4


sorry I meant arctan
Reply 19
Original post by RichE
You wrote, for example, argz = Imz/Rez.

So the argument of 1+i would be 1/1=1??

You mean tan(argz) = Imz/Rez.

So tan arg(1+i) = 1 meaning arg(1+i) = pi/4


thank you for pointing the typo!

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