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Unit 5 chemistry edexecel help!!

1.

Which of the following successive ionization energies (values in kJ mol–1) could have
come from a transition element?
A [font="TimesNewRomanPSMT"]496 4563 6913 9544 13352 16611 20115 25941
B [font="TimesNewRomanPSMT"]590 1145 4912 6474 8144 10496 12320 14207
C [font="TimesNewRomanPSMT"]717 1509 3249 4940 6985 9200 11508 18956
D 2081 3952 6122 9370 12177 15239 19999 23069






WHY IS IT C I AM SOOOO CONFUSED PLEASE I AM BEGGING SOMEONE HELP ME!
Reply 1
Original post by Acer123

1.

Which of the following successive ionization energies (values in kJ mol–1) could have
come from a transition element?
A [font="TimesNewRomanPSMT"]496 4563 6913 9544 13352 16611 20115 25941
B [font="TimesNewRomanPSMT"]590 1145 4912 6474 8144 10496 12320 14207
C [font="TimesNewRomanPSMT"]717 1509 3249 4940 6985 9200 11508 18956
D 2081 3952 6122 9370 12177 15239 19999 23069






WHY IS IT C I AM SOOOO CONFUSED PLEASE I AM BEGGING SOMEONE HELP ME!


Look at where the jump in IE is for each case.

A: Between 1st and 2nd
B: Between 2nd and 3rd
C: Between 7th and 8th
D: Between 6th and 7th

From this, you can deduce that A is in group 1, B is in group 2.

C could be a group 7 but the question states that there must be a transition metal. C is the most likely because the increase in IE is very steady and gradual which is characteristic to a transition metal. Transition metal has 4s orbital and 3d orbital and they are very close in energy level which result in such a steady pattern. With this argument it could be D too but there is another evidence that it is C. There is a mini jump between 2nd and 3rd for C which accounts for the change in 4s and 3d although they are very close in energy level it's still a different energy level.
Also I think C has a very low first IE for group 7 - first IE is supposed to increase across period so it is very likely that C is more towards left side of periodic table. D on the other hand has ridiculously high first IE for something in middle/left of the periodic table.

This is my best shot; I could be a bit off - I'm only Y12 so that should be someone who's more qualified to suggest the reasons.
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(edited 8 years ago)
Reply 2
Original post by C0balt
Look at where the jump in IE is for each case.

A: Between 1st and 2nd
B: Between 2nd and 3rd
C: Between 7th and 8th
D: Between 6th and 7th

From this, you can deduce that A is in group 1, B is in group 2.

C could be a group 7 but the question states that there must be a transition metal. C is the most likely because the increase in IE is very steady and gradual which is characteristic to a transition metal. Transition metal has 4s orbital and 3d orbital and they are very close in energy level which result in such a steady pattern. With this argument it could be D too but there is another evidence that it is C. There is a mini jump between 2nd and 3rd for C which accounts for the change in 4s and 3d although they are very close in energy level it's still a different energy level.
Also I think C has a very low first IE for group 7 - first IE is supposed to increase across period so it is very likely that C is more towards left side of periodic table. D on the other hand has ridiculously high first IE for something in middle/left of the periodic table.

This is my best shot; I could be a bit off - I'm only Y12 so that should be someone who's more qualified to suggest the reasons.
Posted from TSR Mobile


You sir are a legend!
Reply 3
Original post by Acer123
You sir are a legend!


:colondollar:

P.S. I'm no sir :wink:

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