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Difficult Maths/Mechanics Question

Taken straight from OCR Jun 14 Mechanics 2...

A car of mass 800kg travels up a hill inclined at {theta} to the horizontal where sin{theta} = 5/49. There is a constant resistance to motion of 1300N and the car's engine works at a constant rate of 20kW. The car starts from rest and its speed is 8m/s after it has travelled a distance of 22.1m. Calculate the time taken by the car to travel this distance.

Help would be greatly appreciated :smile:
20kW is otherwise expressed as 20000 W. Watts are equal to Force x Distance. Have another go knowing that
Original post by an_atheist
20kW is otherwise expressed as 20000 W. Watts are equal to Force x Distance. Have another go knowing that


Yeah I know that hahaha don't worry. Also, Watts = Force x Velocity
Original post by doucheymcswagson
Yeah I know that hahaha don't worry. Also, Watts = Force x Velocity

As much as i want to help you, i cant because i cant give you a full solution and i personally don't like giving half finished solutions to others.
Have you calculated the force of the mass of the car acting down the slope?
I'd like to know the answer to this question too. Should I be considering the change in potential energy as the GPE increases and comparing this to the power?

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