A particle with speed 20m/s and moves in a straight line. The particle is subjected to a resistance which produce a retardation which is initially 5m/s2which increase uniformly with the distance moved, having a value of 11m/s2 when the particle has moved a distance of 12m. given that the particle has speed v m/s when it had moved a distance xm,show that while particle is in motion,
vdv/dx=-(5+0.5x)