yeah true bt there are really good papers in the physics and math tutor site
those papers will come in handy and its really a good method of revising them!!

Reply 4

PlayerBB

17

Can someone please solve me (ii)

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Reply 5

Student 977

2

Original post by PlayerBB

Can someone please solve me (ii)

Posted from TSR Mobile

Think about what each coordinate should equal.

e.g. (pi)/10 should be at 0.

Therefore you can say that:

(a(pi)/10) + b = 0

Then do that for another coordinate and solve the two simultaneously.

Reply 6

PlayerBB

17

Original post by Student 977

Think about what each coordinate should equal.

e.g. (pi)/10 should be at 0.

Therefore you can say that:

(a(pi)/10) + b = 0

Then do that for another coordinate and solve the two simultaneously.

Oh! Okay thank you so much :biggrin:

Reply 7

mariashehadeh

can you link me to the maths and physics tutor sites?

Reply 8

gdunne42

21

Original post by mariashehadeh

There aren't many practice papers for c12, how are you revising?

It's not a perfect solution but I would do lots of C1 and C2 papers first to test my knowledge. I'd focus most on the recent UK and R papers and stop when I was consistently getting over 90%. I'd save the C12 for final practice of the combined topics.

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(edited 8 years ago)

Reply 9

Angelina1997

OP

2

Original post by mariashehadeh

can you link me to the maths and physics tutor sites?

http://www.physicsandmathstutor.com/

Reply 10

Louisb19

14

Original post by PlayerBB

Can someone please solve me (ii)

Posted from TSR Mobile

Part A

Part B

Reply 11

gdunne42

21

Original post by Louisb19

Part A

Part B

Posted from TSR Mobile
A method was already described above

Alternatively
Two transformations have been performed on the sine curve
It has been stretched x 1/a and translated in x

Consider the difference between P and R, it should be 2pi for a complete sine curve but is only pi so what must a equal?
Now if sin(ax-b) = 0, ax -b must be 0, pi or 2pi
If 2x-b=0 x=pi/10 b=
2x-b=pi x=3pi/5 b=
2x-b=2pi ........

(edited 8 years ago)

Reply 12

aslikirmizi

can someone please put the mark scheme of may 2014 c12???

Reply 13

Ashley_01

3

Can someone plz explain Jan 2014, C12 ques 14 prt b...The integration ques.....

Reply 14

gdunne42

21

Original post by aslikirmizi

can someone please put the mark scheme of may 2014 c12???

It can be downloaded from the edexcel web site
http://qualifications.pearson.com/en/qualifications/edexcel-international-advanced-levels/mathematics.coursematerials.html#filterQuery=category:Pearson-UK:Category%2FExam-materials&filterQuery=category:Pearson-UK :colone:

xam-Series%2FJune-2014

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Reply 15

PlayerBB

17

Original post by gdunne42

Posted from TSR Mobile
A method was already described above

Alternatively
Two transformations have been performed on the sine curve
It has been stretched x 1/a and translated in x

Consider the difference between P and R, it should be 2pi for a complete sine curve but is only pi so what must a equal?
Now if sin(ax-b) = 0, ax -b must be 0, pi or 2pi
If 2x-b=0 x=pi/10 b=
2x-b=pi x=3pi/5 b=
2x-b=2pi ........

Ohh ! Thank you dude so freaking much :biggrin:

, and louis19, your solution on paper also helped very much!! :biggrin:

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(edited 8 years ago)

Reply 16

senshi1

2

Oh plzzz can u solve jan 2014 q 5 part b and c plzzz

Reply 17

Deemajek

Can someone explain part a

Reply 18

Angelina1997

OP

2

Original post by Deemajek

Can someone explain part a

part a in what?
well i think u must be referring to the jan 2014 paper :-
ok so here goes...

To find the coordinates of A and B; look at the graph (the curve is cut by a line), therefore you can equate the 2 equations of the curve and the line.
(1) y=x2-2x-15
(2) y=2x-3

(1)=(2)----> x2-2x-15=2x-3
x2-4x-12=0
(x-6)(x+2)=0

x=6 or x=-2

Sub. x=-2 into (1) or (2):
y=2x-3
=2(-2)-3
=-7 A(-2,-7)<---------coordinates for A

sub. x=6 into (1)

y=2x-3
=2(6)-3
=9 B(6,9) <------------coordinates for B

yeah soo this is it !!
hope this is the part a u were talking abt and hope it helps!

(edited 8 years ago)

Reply 19

abood9612

what time do you guys have the exam?

Edexcel C12 Maths (IAL-AS) 20th May 2015!!!! :)

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