Chemistry-please don't attempt to answer if you don't know what you're talking about!

dazya...you are so rude!! Be grateful for everyone's input!!

i need help with this question, elpaw? hornblower? you guys out there.?


1 ) Suggest why aqueous sodium hydroxide has no reaction with ring-substitued aromatic halogen compounds such as C6H5Cl but reacts readily with haloalkanes such as CH3Cl

IS THIS ANYTHING TO DO WITH LOSS OF ELECTRONS?


ok now this is the big cruncher

2 ) Compound L contains 52.2 % Carbon, 2.7 % hyrdrogen and 44.1 % chlorine by mass. When 1g of L was heated with aqueus sodium hydroxide and the resulting solution treated with an excess of dilute nitric acid followed by aq ag nitrate, 0.892g of silver chloride was formed


Deduce the emp formula for L which is also its molecular formula. Suggest three structures for L. Name and outline a mechanism for the reaction of L with aq sodium hyrdroxide

b) 52.2/12 = 4.35
2.7/1 = 2.7
44.1/35.5 = 1.24

4.35 / 1.24 = 3.5
2.7/1.24 = 2.0
1.24/1.24 = 1.0

C3.5H2Cl

And then just normal nucleophilic substitution by the aq NaOH

b) 52.2/12 = 4.35
2.7/1 = 2.7
44.1/35.5 = 1.24

4.35 / 1.24 = 3.5
2.7/1.24 = 2.0
1.24/1.24 = 1.0

C3.5H2Cl

And then just normal nucleophilic substitution by the aq NaOH

But you can't have 3.5C, so it would have to be C7H4Cl2

Which I've never seen before, looks very odd to me...

i need help with this question, elpaw? hornblower? you guys out there.?


1 ) Suggest why aqueous sodium hydroxide has no reaction with ring-substitued aromatic halogen compounds such as C6H5Cl but reacts readily with haloalkanes such as CH3Cl

IS THIS ANYTHING TO DO WITH LOSS OF ELECTRONS?


ok now this is the big cruncher

2 ) Compound L contains 52.2 % Carbon, 2.7 % hyrdrogen and 44.1 % chlorine by mass. When 1g of L was heated with aqueus sodium hydroxide and the resulting solution treated with an excess of dilute nitric acid followed by aq ag nitrate, 0.892g of silver chloride was formed


Deduce the emp formula for L which is also its molecular formula. Suggest three structures for L. Name and outline a mechanism for the reaction of L with aq sodium hyrdroxide

But you can't have 3.5C, so it would have to be C7H4Cl2

Which I've never seen before, looks very odd to me...

holy fuck - thank you so you could jst put it as:

no wait your equation is wrong but you helped me out lots

C
52.2/12 = 4.35
H 3.72/1 = 3.72
Cl 44.1/35.5 = 1.24

Hence C 3.50, H 2,99 and CL 1


Therefore C7H6Cl2

then the mechanisms?

i need help with this question, elpaw? hornblower? you guys out there.?


1 ) Suggest why aqueous sodium hydroxide has no reaction with ring-substitued aromatic halogen compounds such as C6H5Cl but reacts readily with haloalkanes such as CH3Cl

IS THIS ANYTHING TO DO WITH LOSS OF ELECTRONS?


ok now this is the big cruncher

2 ) Compound L contains 52.2 % Carbon, 2.7 % hyrdrogen and 44.1 % chlorine by mass. When 1g of L was heated with aqueus sodium hydroxide and the resulting solution treated with an excess of dilute nitric acid followed by aq ag nitrate, 0.892g of silver chloride was formed


Deduce the emp formula for L which is also its molecular formula. Suggest three structures for L. Name and outline a mechanism for the reaction of L with aq sodium hyrdroxide

You sad H = 2.7 ?

Helenia: Yeh I thought that was weird as well but it wanted emprical...you cant simply multiply it by 2 as then it isnt the simplest ratio is it?

1) This is to do with the negative inductive effect of the benzene ring. Basically the benzene ring draws electrons away from the polar C -- Cl bond, making it less polar and thus less susceptible to nucleophilic attack. As sodium hydroxide is presemably acting as a nucleophile (through nucleophilic substitution) it will react and displace the d+ chlorine in chloromethane, but not the less polar chlorine atom in chlorobenzene.

so then 1 g gives 0.982g AgCl = 0.982 / 143.5 which = 6.84 x 10^-3 mol

Yes, because it's the simplest whole number ratio. I'd argue that Helenia's ratio is simpler (and also it says the empirical is the same as the molecular, which can't be the case if you have C3.5.)

omgosh thank you

Didnt ask for that though did it?