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OCR MEI C3 Maths June 2015

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help with this question ppl :smile:
Original post by docdoc02
help with this question ppl :smile:


From the graph they have handily given you, you know that:

a(x+b)=x[br]a(x+b)=x[br]
and:
[br]a(x+b)=x[br][br]a(x+b)=-x[br]

Can you do the rest?
(edited 8 years ago)
Original post by Jai Sandhu
From the graph they have handily given you, you know that:

a(x+b)=x[br]a(x+b)=x[br]
and:
[br]a(x+b)=x[br][br]a(x+b)=-x[br]

Can you do the rest?


why cant it be a(-x-b)=-x
or a(-x-b)=x
also i dont understand how they got b=0.25
Original post by docdoc02
help with this question ppl :smile:


Alternatively notice that it is just a transformation of y=xy=|x|. You should be able to easily find b then, and then a.
Original post by lizard54142
Alternatively notice that it is just a transformation of y=xy=|x|. You should be able to easily find b then, and then a.


Spoil sport :tongue: stop stalking me. Btw, I was making reference to part 2 :smile:
Original post by Jai Sandhu
Spoil sport :tongue: stop stalking me.


I watch your every move.

:cyber:
Original post by lizard54142
Alternatively notice that it is just a transformation of y=xy=|x|. You should be able to easily find b then, and then a.


why is b=0.25 and not 0.5?
Original post by docdoc02
why is b=0.25 and not 0.5?


I don't get b as either of those... which past paper is this?
Original post by lizard54142
I don't get b as either of those... which past paper is this?


Yeah... I didn't get b=1/2 or 1/4, I thought I might have done something wrong but I am pretty confident in what I got.
Original post by lizard54142
I don't get b as either of those... which past paper is this?


oh sorry i meant a= 0.5 my bad, i got it right just didnt read the mark scheme properly, it was the june 2013 paper
(edited 8 years ago)
Original post by Jai Sandhu
Yeah... I didn't get b=1/2 or 1/4, I thought I might have done something wrong but I am pretty confident in what I got.


sorry i meant a :/ but i didnt read the mark scheme properly
why cant it be a(-x-b)=-x
or a(-x-b)=x
for the second part
Reply 91
Does anyone have june 2014 paper if yes please post
Original post by docdoc02
sorry i meant a :/ but i didnt read the mark scheme properly
why cant it be a(-x-b)=-x
or a(-x-b)=x
for the second part


Look at the graph and the points at which the 2 lines intersect.
Original post by docdoc02
help with this question ppl :smile:


as it is a transformation of y=IxI, i think b=1 because f(x+1) is a translation of 1 unit to the left parallel to the x-axis, and A i think will be the degree to which the graph is stretched or squashed parallel to the y-axis in relation to the graph of y=IxI
Original post by docdoc02
sorry i meant a :/ but i didnt read the mark scheme properly
why cant it be a(-x-b)=-x
or a(-x-b)=x
for the second part


It can, you've written the same thing as Jai did, just in a different way.

Original post by bapu_01
Does anyone have june 2014 paper if yes please post


http://www.thestudentroom.co.uk/showthread.php?t=3332257&page=3&p=56794477#post56794477
[QUOTE="lizard54142;56853983"]It can, you've written the same thing as Jai did, just in a different way.

Original post by Jai Sandhu
Look at the graph and the points at which the 2 lines intersect.


thank you!
I appreciate the help from the previous question and im stuck on question 5. I understand to use the product rule but not the not until i have got the full differential equation and not simplified yet. after that i dont know how to get the result. thanks.
http://www.mei.org.uk/files/papers/2011_June_c3.pdf
Original post by Velocity_
I appreciate the help from the previous question and im stuck on question 5. I understand to use the product rule but not the not until i have got the full differential equation and not simplified yet. after that i dont know how to get the result. thanks.
http://www.mei.org.uk/files/papers/2011_June_c3.pdf


I don't understand what you've typed... this question is just an application of the product rule. Post your working?
you know when doing proofs you can say even number is 2x, odd number is 2x+1, what others are there e.g. A prime number?
Because i really struggle on these
Original post by Alevelstudent678
you know when doing proofs you can say even number is 2x, odd number is 2x+1, what others are there e.g. A prime number?
Because i really struggle on these


You cannot define a prime number like you would an even or odd number. Make sure you know how to prove 2\sqrt2 is irrational, or 3\sqrt3 is irrational etc...

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