Maths IGCSE Edexcel Paper 3H

HARD! My maths teacher even came up to me afterwards saying it was tough :P

(edited 8 years ago)

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It was meant to be 3H... The easy one. The whole N = 2^22 - 1 was utterly stupid and was not very logical to find out really

(edited 8 years ago)

Axt

Actually that question was fairly logical.

You could either find the prime factors of N or split n into 2 brackets

i.e.
(2^11-1)(2^11+1) that being a possible answer of 2047*2049.

The question is meant to make you apply your knowledge and this just merged indices with factorising.

Reply 4

Itssleah

Original post by neutraltones

It was meant to be 3H... The easy one. The whole N = 2^22 - 1 was utterly stupid and was not very logical to find out really

I got 2^10 (1024) x 2^12.(4096) = 2^22 (4194304)

Reply 5

janster111

Original post by BlackLocust

How about the question with the tangent, circle/triangle ?

Reply 6

gomc

i wrote it was just for the banter

Reply 7

Vlad2dracul

the paper was very difficult. They should definetely lower the grade boundary for an A!

Reply 8

Rup1999

Original post by Vlad2dracul

the paper was very difficult. They should definetely lower the grade boundary for an A!

Yeah I hope they do as well but it's always about 60-65

Reply 9

BlackLocust

Original post by janster111

How about the question with the tangent, circle/triangle ?

I agree that question was hard.

Firstly, mark the centre of the circle and draw the radius from it to the tangent, that angle is then 90.

Then onthe right an isoceles triangle was formed, where the angles were 32,32 and 116.

Then se the straight line at the bottom of the triangle to get 180-116=64

The the angle is 180-90-64=26

This qestion was hard if you coldn't see the connection between centre and tangent. There may be another way to get the answer, bt that was the easiest way i believe.

Therefore the answer was 26 degrees.

Reply 10

BlackLocust

Original post by Itssleah

I got 2^10 (1024) x 2^12.(4096) = 2^22 (4194304)

The answer had to equal 2^22-1, so the answer can only be 2047*2049.

The problem is with the brackets (2^10+1)(2^12-1) is that the answer isn't correct at least that is what me and my friends think, becuase the 2^10 and 2^12 don't cancel out. It helps to thing of it as a difference of two sqares if that helps.

Reply 11

gomc

Original post by Rup1999

Yeah I hope they do as well but it's always about 60-65

rup!!!!!!!!!!!!!!!!!!!!!!!!!!!!! its me!!!!!!!!!!!!!

Reply 12

janster111

Original post by BlackLocust

Yes I got that :biggrin:

Reply 13

janster111

[QUOTE=jmallet;56067449]You can also solve that problem using Alternate Segment Theorem.

Yeh that's the way I did it :smile:

Reply 14

gomc

anyone going to make a list of 4h possible topics? i reckon differentiation, sine/cosine, transformations, surds, rearranging to find subjects and quadratics. anything else?

Reply 15

idied

What's an A*? Is it 85%?

Also if we get over 85% in both papers will you get and A*?

(edited 8 years ago)

Reply 16

idied

How did you do the question about A being proportional to T^2 and also r^3.
when T=47, r =0.25.
find r when T=365??

I found it impossible to do!

Reply 17

janster111

[QUOTE=idied;56068185]What's an A*? Is it 85%?

Also if we get over 85% in both papers will you get and A*?

Definitely, the A* hovers around 79/84 tops.

Reply 18

asox

Original post by gomc

anyone going to make a list of 4h possible topics? i reckon differentiation, sine/cosine, transformations, surds, rearranging to find subjects and quadratics. anything else?

compound interest
differentiation
sine/cosine rules
surds
rearranging
quadratics
transformations chords
rationalising surds
exterior angle calculations
sets
hcf/lcm
inequalities
percentage changes

Reply 19

Yuuchin1

Original post by jmallet

A = kT^2
A = mr^3

kT^2 = mr^3

We are given that when T is 47, r is 0.25

so k47^2 = m0.25^3

we can rearrange this to show that

k/m = 0.25^3/47^2

Now we need to find r when T = 365

k365^2 = mr^3

rearranges to

k/m = r^3/365^2

to

k/m * 365^2 = r^3

we already know the value of k/m, so multiplying this by 365^2 gives r^3 as 0.94235...

Cube rooting this number gives r to be 0.98

lol we even had the same letters- its 0.980 tho cos its 3sf