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OCR MEI C2 Mathematics [June 3rd 2015]

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Capture.JPGCould i have help on this sequence question please.know that r is 2.5
Original post by SilentReader_1
Capture.JPGCould i have help on this sequence question please.know that r is 2.5


sum to infinity = a/(1-r)
r is 2/5 and a is 5
Reply 82
Avatar for aecon29
aecon29
image.jpgHow do you solve question 7 ? It's may 2011
June 2014 was quite an easy paper. I hope we get another like that.

Any tips on those trig questions which are sometimes at the end of the paper?
Original post by AlexParmenter
I think begin by dividing both sides by tan


I would convert tan to sin/cos and go from there.
Original post by AlecRobertson
I would convert tan to sin/cos and go from there.


yeah you're right that's what the mark scheme says lol, woud it work if you were to divide by tan though because you'd get 1=2cosθ ?
Post up your working I don't have any paper on me :smile:
Can anyone help me with this question? I know Cos=Adj/Hyp
Question 1
Thanks
image.jpg
Original post by aecon29
image.jpgHow do you solve question 7 ? It's may 2011


I done sin/cos = 2sin

sin = (cos)(2sin)

sin/2sin = cos

therefore cos = 1/2

so cos-1(1/2) = 60 and 300

Not to sure if thats correct but it seems to work :smile:
Reply 89
Avatar for Aph
Aph
22
Original post by 1997_1997
Can anyone help me with this question? I know Cos=Adj/Hyp
Question 1
Thanks
image.jpg


If 2 of the sides have length 1 what must the other be?
Original post by AlecRobertson
Advice for trig: buy a graphical calculator. It makes it soooo easy.



I have a graphical calculator! I just don't know how to use it


Posted from TSR Mobile
Original post by Aph
If 2 of the sides have length 1 what must the other be?


So would the answer just be this?image.jpg
Reply 92
Avatar for Joseph97
Joseph97
what are some tricky questions or concepts I need to go over? I'm aiming for 95+%
Original post by chelsomer
I done sin/cos = 2sin

sin = (cos)(2sin)

sin/2sin = cos

therefore cos = 1/2

so cos-1(1/2) = 60 and 300

Not to sure if thats correct but it seems to work :smile:


Beware! Your third step onwards means you will lose some solutions...

I'd recommend bringing sin over to the right-hand side so that everything is equal to zero, i.e. 0 = 2sinθcosθ-sinθ. Factorise (common factors) and solve from there. You'll find there are 3 more solutions!
Reply 94
Avatar for Aph
Aph
22
Original post by 1997_1997
So would the answer just be this?image.jpg


That's what it's asking for, and just say that sin=...
Reply 95
Avatar for Jim997
Jim997
2
Original post by Supergirlxxxxxx
I have a graphical calculator! I just don't know how to use it


Posted from TSR Mobile


What a tremendous waste of money then
Reply 96
Avatar for Jim997
Jim997
2
Original post by Aph
That's what it's asking for, and just say that sin=...


You mean cos sunshine
Original post by Aph
That's what it's asking for, and just say that sin=...


Ohh thank youu 🙈
In integration questions, do you have to write:

kx^7/2 + c
k = 2

or can you write 2x^7/2 + c

to get all the marks?

Screen Shot 2015-06-02 at 18.17.16.png9.7KB
Just in case anyone in year 13 decides to skim through this thread, what are C3/C4 and/or FP2 like in terms of difficulty in comparison to C2 and/or FP1?

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