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epimers, enantiomers, diastereoisomers confusion:s - pic attached

Hi,

So my lecturer says that the two carbohydrates attached are..
Epimers and enantiomers

But I can't see how they are Enantiomers as they aren't mirror images are they?

Any help would be appreciated as I'm really struggling with this idea
Thanks in advance(:
Reply 1
Original post by ThePremierLeague
Hi,

So my lecturer says that the two carbohydrates attached are..
Epimers and enantiomers

But I can't see how they are Enantiomers as they aren't mirror images are they?

Any help would be appreciated as I'm really struggling with this idea
Thanks in advance(:


They are mirror images :smile:

Enantiomers are like your left and right hands, they are mirror images but if you tried to place one on top of another, they just don't match.
Original post by NDVA
They are mirror images :smile:

Enantiomers are like your left and right hands, they are mirror images but if you tried to place one on top of another, they just don't match.


But if something's a mirror image, surely if you try to placed one on top of the other it has to match?

I'm so confused right now haha
Reply 3
Original post by ThePremierLeague
But if something's a mirror image, surely if you try to placed one on top of the other it has to match?

I'm so confused right now haha


Have a look at this picture :smile:

Optical Isomers.jpg
Original post by NDVA
Have a look at this picture :smile:

Optical Isomers.jpg


thank you.

Have you got a link for the pic pls? It won't open from here for some reason :s
Reply 5
Original post by ThePremierLeague
thank you.

Have you got a link for the pic pls? It won't open from here for some reason :s


http://bcs.whfreeman.com/thelifewire8e/content/cat_010/f03002.jpg

I just Googled it :smile:



Thanks mate.

I think I've just realised why I've been struggling with this idea...

Because the top part (CHO) if you take the atoms individually, they don't make a mirror image...

But if you take the molecules in their Fischer Projection (i.e CHO)... then the mirror image thing does make sense.

Am I correct?:smile:
Reply 7
Original post by ThePremierLeague
Thanks mate.

I think I've just realised why I've been struggling with this idea...

Because the top part (CHO) if you take the atoms individually, they don't make a mirror image...

But if you take the molecules in their Fischer Projection (i.e CHO)... then the mirror image thing does make sense.

Am I correct?:smile:


Yes, it is the molecule (chiral carbon atom and four different groups around it) and its projection that are mirror images to each other. So you have to look at a whole molecule, not just the CHO part :smile:
Original post by NDVA
Yes, it is the molecule (chiral carbon atom and four different groups around it) and its projection that are mirror images to each other. So you have to look at a whole molecule, not just the CHO part :smile:


Ah that makes sense now.

I was trying to reflect the H and O atoms from the top of the molecule, so I kept getting H from L-glyceraldehyde on the O from D-glyceraldehyde haha.

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