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m1 maths 2014 ocr help

Hey could anyone help me with the last part of this question. (iiia,b) Link provided.
Screenshot 2015-06-04 20.05.16.png129.0KB
Original post by James Cameron
Hey could anyone help me with the last part of this question. (iiia,b) Link provided.


What have you tried so far?
Original post by lizard54142
What have you tried so far?


finally did the first part after realising that friction acts to the right so

tcos0-3=3
got t=6 for the first part

for the second part i resolved vertically to find (R)
got 8-tsin30
then i resolved vertically and got
tcos30-3

i put them into the equation f=mr given that mu=0.375
now i have 0.375=tcos30-3/8-tsin30 but i'm unable to proceed to find t
Original post by James Cameron
finally did the first part after realising that friction acts to the right so

tcos0-3=3
got t=6 for the first part

for the second part i resolved vertically to find (R)
got 8-tsin30
then i resolved vertically and got
tcos30-3

i put them into the equation f=mr given that mu=0.375
now i have 0.375=tcos30-3/8-tsin30 but i'm unable to proceed to find t


Try and get all the terms involving t on one side of your equation, and all the other terms on the other side. Get rid of any fractions. It is a bit unclear what you have typed, is it meant to be this:

0.375=tcos30−38−tsin300.375= \dfrac{tcos30 - 3}{8 - tsin30}
Original post by lizard54142
Try and get all the terms involving t on one side of your equation, and all the other terms on the other side. Get rid of any fractions. It is a bit unclear what you have typed, is it meant to be this:

0.375=tcos30−38−tsin300.375= \dfrac{tcos30 - 3}{8 - tsin30}


thanks man i got t=5.69. not sure if that's right though... but yes that's what i did type
Original post by James Cameron
thanks man i got t=5.69. not sure if that's right though... but yes that's what i did type


Looks good to me!

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