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OCR MEI Numerical Methods 12th June 2015

I'm surprised there wasn't a specific thread for this exam.

Anyways, how is everyone feeling about this test? Personally, I think its just a slightly more structured form of D1.:colonhash:

Strengths + weaknesses? :h:

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Numerical methods is horrible, I'm resitting this year.

I'm finding it easier than last time I did it though so hopefully I can get this over 80%.

I remember last year the test was awful...


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Reply 2
Original post by Genty Boy
Numerical methods is horrible, I'm resitting this year.

I'm finding it easier than last time I did it though so hopefully I can get this over 80%.

I remember last year the test was awful...


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Ahhh right, was it really?
Isn't the structure of NM papers practically the same each time?

How good are you with Connection Rule, extrapolation and nth-order convergence stuff?

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I don't know what you mean by connection rule. Other stuff, yeah fine.

They are the same lay out every year but the 2014 paper had a weird question on Midpoint Trapezium and Simpsons rule which caught a lot of people out.


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Reply 4
does anyone have the chapter assessment for chapter 4 approximating functions from integral maths which I could please have?
Reply 5
Original post by Genty Boy
I don't know what you mean by connection rule. Other stuff, yeah fine.

They are the same lay out every year but the 2014 paper had a weird question on Midpoint Trapezium and Simpsons rule which caught a lot of people out.


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The connection rule is basically how each rule links with eachother. You're not given the formulas.
S= Simpson's Rule
M=Midpoint Rule
T=Trapezium Rule

S(n): = [2M(n) +T(n)]/3
where (n) is a subscript representing the number of strips

T(2n): [M(n) + T(n)]/2

It's just errors I'm not good with.

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Reply 6
Original post by runny4
does anyone have the chapter assessment for chapter 4 approximating functions from integral maths which I could please have?


I do, I'll link it to you here:
http://integralmaths.org/mod/resource/view.php?id=3506:redface:

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Reply 7


thanks and do u have the answers?
Original post by Leechayy
The connection rule is basically how each rule links with eachother. You're not given the formulas.
S= Simpson's Rule
M=Midpoint Rule
T=Trapezium Rule

S(n): = [2M(n) +T(n)]/3
where (n) is a subscript representing the number of strips

T(2n): [M(n) + T(n)]/2

It's just errors I'm not good with.

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Oh yeah, that's alright


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This module sucks. Have done barely any revision for it, it's so dull.
Reply 10
Original post by lizard54142
This module sucks. Have done barely any revision for it, it's so dull.


It's true, personally look at your coursework.
All the more difficult topics are covered when doing the coursework.
Then learn to do all questions in tabular form:tongue:
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Original post by Leechayy
It's true, personally look at your coursework.
All the more difficult topics are covered when doing the coursework.
Then learn to do all questions in tabular form:tongue:
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I got 17 on my coursework because the teacher said it's safer to give 17 than 18... :frown:

I just have no motivation to study for this.
Reply 12
Original post by lizard54142
I got 17 on my coursework because the teacher said it's safer to give 17 than 18... :frown:

I just have no motivation to study for this.


Same here I have around 15-17 marks but something about OCR coming in to moderate everyone to check if it is valid is why there're so many 17's :frown:

It's such a boring topic I know.
It's the memory test of maths lol
Reply 13
Hi i was wondering if anyone could help me with this question please its off June 2009: The numbers X and Y shown below are known to be correct to 3 decimal places.X = 2.718 Y = 3.142

1.

(i) State the maximum possible errors in X, X + Y, X Y, 10X + 20Y. [4]

2.

(ii) Find the maximum possible relative errors in X and Y. Hence state approximately the maximum possible relative errors in XY and XY.

Thanks :smile:
Original post by Keys10
Hi i was wondering if anyone could help me with this question please its off June 2009: The numbers X and Y shown below are known to be correct to 3 decimal places.X = 2.718 Y = 3.142

1.

(i) State the maximum possible errors in X, X + Y, X Y, 10X + 20Y. [4]

2.

(ii) Find the maximum possible relative errors in X and Y. Hence state approximately the maximum possible relative errors in XY and XY.

Thanks :smile:


What are you stuck on?

2.7175X2.71852.7175 \leq X \leq 2.7185

3.1415Y3.14253.1415 \leq Y \leq 3.1425
Reply 15
Original post by lizard54142
What are you stuck on?

2.7175X2.71852.7175 \leq X \leq 2.7185

3.1415Y3.14253.1415 \leq Y \leq 3.1425



Thanks for the quick reply

what i don't understand is what the maximum possible for X and Y are to solve the other parts?
Original post by Keys10
Hi i was wondering if anyone could help me with this question please its off June 2009: The numbers X and Y shown below are known to be correct to 3 decimal places.X = 2.718 Y = 3.142

1.

(i) State the maximum possible errors in X, X + Y, X Y, 10X + 20Y. [4]

2.

(ii) Find the maximum possible relative errors in X and Y. Hence state approximately the maximumpossible relative errors in XY and XY.

Thanks :smile:


It's 3dp so max p error = .0005

So X - .0005

X+/-Y - .001

10(.0005)+20(.0005) - .015

Then find relative errors in both X and Y

For X it would be (2.7185-2.718)/2.718

So for XY and X/Y you just add the individual relative errors in both cases which comes to .000343

Hope that helps. Al.


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Original post by Keys10
Thanks for the quick reply

what i don't understand is what the maximum possible for X and Y are to solve the other parts?


The maximum possible error is the largest possible value of "approximation - true value".
Reply 18
Original post by Genty Boy
It's 3dp so max p error = .0005

So X - .0005

X+/-Y - .001

10(.0005)+20(.0005) - .015

Then find relative errors in both X and Y

For X it would be (2.7185-2.718)/2.718

So for XY and X/Y you just add the individual relative errors in both cases which comes to .000343

Hope that helps. Al.


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Thanks for that so in the part X+/-Y does that mean the highest possible value for X and the lowest possible value for Y??
Original post by Keys10
Thanks for that so in the part X+/-Y does that mean the highest possible value for X and the lowest possible value for Y??


It doesn't matter- they are errors so don't think of them as adding or subtracting errors. They are always added because each thing you add to an equation, you are adding the error that comes with it- you can't really "undo" an error so it won't be subtracted.


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