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AS chemistry mod 3....aaaaaargh!

Okies....mod 3 is driving me totally insane. Can somebody please tell me if i've managed to come anywhere near the right answer with this question...

Give the stuctural formulae of the two alkenes obtained when 2-bromo-2-methylbutane reacts with ethanolic potassium hydroxide. Deduce the names of the two products.
I figured it was an elimination and ended up with

1) CH3CCH3=CHCH3
2-methylbut-2-ene

2) CH2=CCH3CH2CH3
2-methylbut-1-ene

is this at all correct in any way?!...also if it is, can't u get cis-trans isomerism on the 1st one?

Reply 1

Happyelf

OP

please please please somebody help!!

Reply 2

z!D4N

Happyelf

Okies....mod 3 is driving me totally insane. Can somebody please tell me if i've managed to come anywhere near the right answer with this question...

Give the stuctural formulae of the two alkenes obtained when 2-bromo-2-methylbutane reacts with ethanolic potassium hydroxide. Deduce the names of the two products.
I figured it was an elimination and ended up with

1) CH3CCH3=CHCH3
2-methylbut-2-ene

2) CH2=CCH3CH2CH3
2-methylbut-1-ene

is this at all correct in any way?!...also if it is, can't u get cis-trans isomerism on the 1st one?

Basically, all the bromine atoms are being eliminated and you get the alkenes back.

er... i'm not sure of the cis-trans one... cant be bothered to draw it out... but just look at it if it could be different due to the restriction of rotation about the double carbon-carbon bond...

Reply 3

z!D4N

im willing to answer other questions but not draw things plz lol.

Reply 4

Happyelf

OP

okies...so is that right what i have done then (ignoring the cis-trans thing)

Reply 5

IntegralAnomaly

Happyelf

okies...so is that right what i have done then (ignoring the cis-trans thing)

there's no cis and trans isomerism.

Reply 6

Happyelf

OP

is the first bit right tho?

Reply 7

Barny

17

I got 2-methylbut-3-ene

Reply 8

Happyelf

OP

imasillynarb

I got 2-methylbut-3-ene

u can't get but-3-ene....cos u have to number the functional group with the lowest number possible. if u turn the molecule round it will be the same as but-1-ene or but-2-ene i think. can't be bothered drawing it

Reply 9

supreme

4

Happyelf

Okies....mod 3 is driving me totally insane. Can somebody please tell me if i've managed to come anywhere near the right answer with this question...

Give the stuctural formulae of the two alkenes obtained when 2-bromo-2-methylbutane reacts with ethanolic potassium hydroxide. Deduce the names of the two products.
I figured it was an elimination and ended up with

1) CH3CCH3=CHCH3
2-methylbut-2-ene

2) CH2=CCH3CH2CH3
2-methylbut-1-ene

is this at all correct in any way?!...also if it is, can't u get cis-trans isomerism on the 1st one?

I get 2-methylbut-1-ene and 2-methylbut-2-ene but I am guarantying that I am right.

AS chemistry mod 3....aaaaaargh!

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