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parametric differentiation

x=1/(t+1) and
y=(t^2 + 4)

does dy/dx = -2t (t+1)^2

i.e.

x= 1 over (t +1)

y = t squared + 4

therefore dy/dx = -2t times by (t+1)squared.

Can someone confirm please!

Reply 1

ElizabethHere

Original post by luddite

x=1/(t+1) and
y=(t^2 + 4)

does dy/dx = -2t (t+1)^2

i.e.

x= 1 over (t +1)

y = t squared + 4

therefore dy/dx = -2t times by (t+1)squared.

Can someone confirm please!

Where did you get D from?

Reply 2

ElizabethHere

I got t^3 + t^2 + 4t+ 4 but I may be completely wrong.

Reply 3

tiny hobbit

Original post by luddite

x=1/(t+1) and
y=(t^2 + 4)

does dy/dx = -2t (t+1)^2

i.e.

x= 1 over (t +1)

y = t squared + 4

therefore dy/dx = -2t times by (t+1)squared.

Can someone confirm please!

Yep.

Reply 4

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