The Student Room Group
Reply 1
whats the standard differential for x^m.y^n dx?


not very sure, about the question can you please clarify about the dx part.

n e way this is what i got

u = x^m
V = Y^n

Du/dx = mx^(m-1)
Dv/dx = ny^(n-1). Dy/dx

use the product rule and solve.... a long answer which i cant get my self to type.... btw do you haf any idea how to answer the circle question i posted in the acedemic forum (P3 mock paper - 8d)
Reply 2
powerball
whats the standard differential for x^m.y^n ?

edit* whoops dx was an accident

By implicit differentiation and using the product rule:

d/dx of x^m.y^n=mx^(m-1).y^n+n.x^m.y^(n-1).dy/dx

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