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Why does solid Phosphorus have 4 atoms?

I'm currently doing some chemistry questions (page 18 of OCR AS & Year 1 textbook).

This is the question:

Write a balanced with state symbols for the following reaction:

Magnesium reacts with solid phosphorus to form solid magnesium phosphide.

The answer, according to the back of the book says:

6Mg + P⁴ 2Mg³P²


My question is how can you know or work out that solid Phosphorus in the product has four atoms? Same goes the Mg and the P in the result have their respective 3 and 2 atoms (all before balancing out the equation).
Original post by Grashex
I'm currently doing some chemistry questions (page 18 of OCR AS & Year 1 textbook).

This is the question:

Write a balanced with state symbols for the following reaction:

Magnesium reacts with solid phosphorus to form solid magnesium phosphide.

The answer, according to the back of the book says:

6Mg + P⁴ 2Mg³P²


My question is how can you know or work out that solid Phosphorus in the product has four atoms? Same goes the Mg and the P in the result have their respective 3 and 2 atoms (all before balancing out the equation).


It's just something that you have to learn...

Phosphorus exists as simple P4 pyramidal molecules, sulfur as S8 crown shaped molecules.

P4.gif
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