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Quadratic Help

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Please can someone explain to me how to do Question 11
Original post by Vicb123
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Please can someone explain to me how to do Question 11


Let width be X. Then length is X+4 and height is X+1. Picture a box, the longer length is from the bottom corner of one side to the top corner of the other.

Then it's just pythag. in 3D. A^2 = B^2 + C^2 + D^2.
So 7.5^2 = X^2 + (X+4)^2 + (X+1)^2
Factorise it out and solve :smile:
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Vicb123
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Original post by MattyJMP
Let width be X. Then length is X+4 and height is X+1. Picture a box, the longer length is from the bottom corner of one side to the top corner of the other.

Then it's just pythag. in 3D. A^2 = B^2 + C^2 + D^2.
So 7.5^2 = X^2 + (X+4)^2 + (X+1)^2
Factorise it out and solve :smile:


Thank you for your help:smile:

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