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product and chain rule

y= (3x+2)^2 * e^7x

Could anyone please tell me how I would differentiate this?
You've already separated it into two multiplicands, so how about applying the product rule? :smile:
Reply 2
Avatar for bazj
bazj
OP
Thank you:smile:

just to check, would you need to expand (3x+2)^2 or leave it in the brackets?
u=(3x+2)^2 V=e^7x
**u'=6(3x+2) V'=7e^7x

y'=e^7x*6(3x+2)+7e^7x*(3x+2)^2


**using chain rule: z=(3x+2)^2
w=3x+2 q=w^2
w'=3 q'=2w

z'=6(3x+2)
(edited 8 years ago)
Reply 4
Avatar for bazj
bazj
OP
Thank you!:smile:
Original post by wispaedits
...


Posting full solutions is against the forum rules.
Original post by morgan8002
Posting full solutions is against the forum rules.


link said rules?
Original post by wispaedits
link said rules?



http://www.thestudentroom.co.uk/showthread.php?t=403989
Original post by morgan8002


"posting full solutions is frowned upon"
Original post by wispaedits
"posting full solutions is frowned upon"


This is a thorny topic, which has probably caused more arguments than anything else on this forum. To make it perfectly clear, the consensus (and forum rule), is that posting of full solutions should be considered a last resort. If your first contribution to a thread is to post a full solution, the moderators are quite entitled to take action.


You didn't try to nudge bazj in the right direction like Mpagtches. Instead you told the user the answer straight away, denying them the chance to work it out for themselves.

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