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Help with this quick question please!!!!

The line AB has equation 3x+2y=7. The point C has coordinates (2,-7)
Gradient is -3/2


The line which passes through C and which is parallel to AB crosses the y-axis at the point D. Fine the y-coordinates of D.



Idk how to get to the answer (0,-4) or something? Please somebody give me a step by step saying exactly whats happening :frown:

Thanks
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AH127
12
You know the gradient of the line passing through C because it's parallel to AB, which means the gradient is the same. Put your x and y values for C in to y-y(1)=m(x-x(1)) to find the equation for that line, and then substitute x=0 in to that equation.
Original post by Tarlius
The line AB has equation 3x+2y=7. The point C has coordinates (2,-7)
Gradient is -3/2


The line which passes through C and which is parallel to AB crosses the y-axis at the point D. Fine the y-coordinates of D.



Idk how to get to the answer (0,-4) or something? Please somebody give me a step by step saying exactly whats happening :frown:

Thanks


Hi :smile:
Please see my detailed solution to obtain final answer (0,-4):
1444480425864.jpg

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