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points of intersection.

can you find the points of intersection between (x-1)(x+1)(x+3)= (x+3)(x+3)/3 ,

or is it impossible. ( the (x+3)(x+3) ) is ALL divided by 3
Original post by ihatehannah
can you find the points of intersection between (x-1)(x+1)(x+3)= (x+3)(x+3)/3 ,

or is it impossible. ( the (x+3)(x+3) ) is ALL divided by 3


If you start to work through it you can either prove or disprove that there are no points of intersection.

How would you try to find them?
Reply 2
Original post by ihatehannah
can you find the points of intersection between (x-1)(x+1)(x+3)= (x+3)(x+3)/3 ,

or is it impossible. ( the (x+3)(x+3) ) is ALL divided by 3


Both sides appear to have a common factor (x+3). So deal with that factor first, then divide both sides by that factor (when it isn't zero) to get a simpler function you can check for points of intersection.
Original post by davros
Both sides appear to have a common factor (x+3). So deal with that factor first, then divide both sides by that factor (when it isn't zero) to get a simpler function you can check for points of intersection.


but it dosen't work,
Reply 4
Original post by ihatehannah
but it dosen't work,


What "doesn't work"?

What have you done so far, what overall answer do you get, and what is the answer supposed to be?
Original post by davros
What "doesn't work"?

What have you done so far, what overall answer do you get, and what is the answer supposed to be?


they intersect at 8, 1296 apparently
Reply 6
Original post by ihatehannah
they intersect at 8, 1296 apparently


Is that supposed to be a pair of (x,y) coordinates i.e. x = 8, y = 1296?

You can see that isn't right if you put x = 8 in both sides of your original equation!

Do you have a screenshot of the original question? I get 2 messy answers for x when I try to solve!
Original post by davros
Is that supposed to be a pair of (x,y) coordinates i.e. x = 8, y = 1296?

You can see that isn't right if you put x = 8 in both sides of your original equation!

Do you have a screenshot of the original question? I get 2 messy answers for x when I try to solve!


hmm ok , let me take a screenshot if i can
Original post by davros
Is that supposed to be a pair of (x,y) coordinates i.e. x = 8, y = 1296?

You can see that isn't right if you put x = 8 in both sides of your original equation!

Do you have a screenshot of the original question? I get 2 messy answers for x when I try to solve!


ughh can't connect my phone to my comp, no usb to do that.
o waiiit ok i kno how to take a screenshot.
Original post by davros
Is that supposed to be a pair of (x,y) coordinates i.e. x = 8, y = 1296?

You can see that isn't right if you put x = 8 in both sides of your original equation!

Do you have a screenshot of the original question? I get 2 messy answers for x when I try to solve!


ok here we go. part II the (2-x) is to the power of 4
(edited 8 years ago)
Reply 11
Original post by ihatehannah
ok here we go. part II the (2-x) is to the power of 4


I'm confused - the question you've uploaded looks nothing like the one in your original post :confused:

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