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Can anyone help me with this physics question?

A capacitor is charged by means of a constant current of 24μA to a pd of 4.2V in 38s. The capacitor is then charged from 4.2V by means of a current of 14μA in 50s. Calculate:

a) charge stored a pd of 4.2V (I got 912μC)
b) the capacitance of the capacitor (I got 217μC)
c) the extra charge stored at a current of 14μA (I got 700μC)
d) the pd after the extra charge was stored - I am a little confused on this one.

Would anyone be able to help me on the last bit?
Original post by Parrotperson
A capacitor is charged by means of a constant current of 24μA to a pd of 4.2V in 38s. The capacitor is then charged from 4.2V by means of a current of 14μA in 50s. Calculate:

a) charge stored a pd of 4.2V (I got 912μC)
b) the capacitance of the capacitor (I got 217μC)
c) the extra charge stored at a current of 14μA (I got 700μC)
d) the pd after the extra charge was stored - I am a little confused on this one.

Would anyone be able to help me on the last bit?


You have worked out the capacitance and the total charge of the capacitor? Can you see how you could work it out?

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