Maths Core 3 - need help

Need help with part a of this c3 maths question, can't seem to get it

Turn the 2cosec2A into 2/sin2A and the cotA into cosA/SinA. Then convert the 2/2Sin2A into 2/2SinACosA (because Sin2A = 2SinACosA). Cancel the 2's as you will have 2/2SinACosA, so that become 1 / SinACosA. Then you want to have a common denominator so you multiply (top and bottom) of the cosA/SinA by cosA so that you have a common denominator of SinACosA. Then you put the fractions together and you get 1-cos^2A (because CosA*CosA = cos^2A) / SinACosA. 1 - Cos^2A is the same as Sin^2A so change the top to that. Then divide top and bottom by SinA. The top will become SinA and the bottom will become Cos A (because SinACosA divided by SinA = CosA as the SinA divided by SinA = 1 so you have 1*CosA which is just CosA. Then you have SinA / CosA which is the same as tanA. Hope that helps.