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Product rule C3

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I don't understand this transition at all, any ideas??


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Original post by Abby5001
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I don't understand this transition at all, any ideas??


Posted from TSR Mobile


They have factorised it.
(edited 8 years ago)
Reply 2
Original post by 16Characters....
They have factorised it.


I know it must be blindingly obvious to you but I can't really see it for some reason


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Original post by Abby5001
I know it must be blindingly obvious to you but I can't really see it for some reason


Posted from TSR Mobile


If we for the moment replace 1+3x 1 + 3x with the letter u our expression is:

15xu4+u5 15xu^4 + u^5 .

Both terms have a common factor of u4u^4 (the first term has 15x lots of u^4, the last term has u lots) so we can bring this common factor out as:

(15x+u)u4(15x + u)u^4

Which when we replace u by 1 + 3x again is:

(15x+1+3x)(1+3x)4(15x + 1 + 3x)(1 + 3x)^4

Is that any clearer?

This form of factorisation confused some members of my AS further maths class; the key thing is to recognise that you can treat the bracket as you would a single letter when factorising.
(edited 8 years ago)
Reply 4
Original post by 16Characters....
If we for the moment replace 1+3x 1 + 3x with the letter u our expression is:

15xu4+u5 15xu^4 + u^5 .

Both terms have a common factor of u4u^4 (the first term has 15x lots of u^4, the last term has u lots) so we can bring this common factor out as:

(15x+u)u4(15x + u)u^4

Which when we replace u by 1 + 3x again is:

(15x+1+3x)(1+3x)4(15x + 1 + 3x)(1 + 3x)^4

Is that any clearer?

This form of factorisation confused some members of my AS further maths class; the key thing is to recognise that you can treat the bracket as you would a single letter when factorising.


That makes a lot more sense, Thankyou


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