The Student Room Group
Uni students - Complete our survey >>
Uni students - Complete our survey >>
Uni students - Complete our survey >>

differentiate

Please can some one shed some light on the attached problem




Thanks in advance
Combining differe. rules_3.pdf326.5KB
Could you make a file where all the text actually fits in?

I'm going to assume that you are asking where those answers come from.

y=uv

dy/dx= u(dv/dx)+v(du/dx)

edit: also that should be a 3x^2
(edited 8 years ago)
It's the product rule.
But the answer is wrong.
(edited 8 years ago)
Original post by zamzam
Please can some one shed some light on the attached problem




Thanks in advance


It is difficult to help you unless we can see the entire question :-)

Also if g(x)=(x2+1)(x3+1) g(x) = (x^2 + 1)(x^3 + 1) then g′(x)=3x2(x2+1)+2x(x3+1) g'(x) = 3x^2(x^2+1) + 2x(x^3 + 1) (so it is 3x23x^2 not 3x3x)

This is what is called the product rule. The product rule states that for functions u and v, if y=uv y = uv then:

dydx=udvdx+vdudx \frac{dy}{dx} = u\frac{dv}{dx} + v\frac{du}{dx}

(Sorry if you already knew what the product rule is, I am not completely sure what your issue is so I just provided as complete an explanation as I could)

Hope this helped.
Reply 4
Avatar for zamzam
zamzam
OP
1
Thanks for all the responses:smile:

Quick Reply

Related discussions

Latest

Trending

Trending

Articles for you