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Need help with calculating percent error

14481365484601598388980.jpg I have idea if that's how u do it, could anyone please explain. Thanks
Reply 1
It isn't 22.15, which makes your second 0.005 wrong.

Also, your first 0.005 was also wrong.

Percentage error = maximum error (in this case is x2 since there are two readings needed for a difference in temp) divided by the reading (in this case it is the difference in reading) x 100, i.e. 2 x 0.05 / 20 x 100
Reply 2
Original post by Pigster
It isn't 22.15, which makes your second 0.005 wrong.

Also, your first 0.005 was also wrong.

Percentage error = maximum error (in this case is x2 since there are two readings needed for a difference in temp) divided by the reading (in this case it is the difference in reading) x 100, i.e. 2 x 0.05 / 20 x 100

Hi, I don't understand why it is 0.05 because on the top of the sheet it says it will be one division, so wouldn't a be 0.1 and be be 0.2? And you have to calculate two answers so they are separate so why would you multiply it by 2?? Thanks
Reply 3
You can read half of a division, hence half of 0.1.

You are measuring a temperature change - the initial temperature is subject to a +/-0.05 and the final temp is also subject to +/-0.05, overall, the uncertainty is 2x+/-0.05 i.e. +/-0.1.
Reply 4
Original post by Pigster
You can read half of a division, hence half of 0.1.

You are measuring a temperature change - the initial temperature is subject to a +/-0.05 and the final temp is also subject to +/-0.05, overall, the uncertainty is 2x+/-0.05 i.e. +/-0.1.


What's the difference between using one division and half of a division? I know it is more precise but it says to use one divison also be wouldn't be the same as a because one division is 0.2 . Right? Thanks
(edited 8 years ago)
Reply 5
Maximum error when measuring change is one division.

The error for one measurement is 0.05 for A and 0.1 for B.

Two reading, to get a temp change is 2x0.05 = 0.1 (one division) for A and 2x0.1 = 0.2 (one division) for B.

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