The Student Room Group

M2 Circular Motion Question

How do I do question 2? As you can see my solution is invalid for the domain of the inverse cosine function since it is not between -1 and 1. I didn't draw a diagram for this one because it models exactly the same situation is above in question 1. The answer in the book gave theta to equal 57 degrees. So I put this in and went backwards, my first equation in terms of sine holds true but the second one for cosine does not. Can someone explain what happened?bimage.jpg
Original post by Mathematicus65
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v=rω  ⟹  v2=r2ω2v=r\omega \implies v^2=r^2\omega^2

Not checked past that.
Original post by ghostwalker
v=rω  ⟹  v2=r2ω2v=r\omega \implies v^2=r^2\omega^2

Not checked past that.

Oh god ...thank you

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