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Graph the inequality |x| + |y| =< 1

HI, i totally have no clue on how to draw the graph for that inequality. Any help would be highly appreciated.
Original post by lyamlim97
HI, i totally have no clue on how to draw the graph for that inequality. Any help would be highly appreciated.


Separate out some cases: first of all, think about the quadrant where x>=0 and y>=0. Here the equation reduces to x + y <= 1 - what does that look like in this quadrant? Now do another quadrant x>=0 and y<=0. What does |y| look like in this quadrant? So re-write the equation to be valid in this quadrant. Rinse and repeat...
Original post by lyamlim97
HI, i totally have no clue on how to draw the graph for that inequality. Any help would be highly appreciated.


Split into 4 cases:

x,y>0

x>0 y<0

x<0 y>0

x,y < 0

on each case you can get rid of the abs function because you know the sign of x,y on that region.

Sketch the 4 cases it should because obvious what the region is.

:smile:

Gregorius just too fast for me :frown:
Reply 4
Thanks everyone. I got it already.

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