The C on the left has four bonds - one to the (CH2)4 group, two to the O in the C=O, where does the bond dangling off the left hand of the polymer go to?
The C on the left has four bonds - one to the (CH2)4 group, two to the O in the C=O, where does the bond dangling off the left hand of the polymer go to?
What kind of bond it that?
From what you said ester, but I don't get how you deduced that.
It was just a train of conversation to try to get you to recognise what was there: a di-acid and an amino-alcohol, hence why you'd get amide and an ester linkages.
The best thing to do in these situations is to draw out the full displayed formula, ensuring that each C has four bonds.
It was just a train of conversation to try to get you to recognise what was there: a di-acid and an amino-alcohol, hence why you'd get amide and an ester linkages.
The best thing to do in these situations is to draw out the full displayed formula, ensuring that each C has four bonds.
Oh of course! It said polymer, I was reading monomer :/