Oxidation numbers
I need to find the oxidation numbers
2Sr(NO3)2(s) → 2SrO(s) + 4NO2(g) + O2(g)
so far on the lhs:
i GOT
Sr= +2
N=+5
O= -6
the oxygen is wrong and the N is right. Don't know about Sr.
2Sr(NO3)2(s) → 2SrO(s) + 4NO2(g) + O2(g)
so far on the lhs:
i GOT
Sr= +2
N=+5
O= -6
the oxygen is wrong and the N is right. Don't know about Sr.
(edited 8 years ago)
In H2SO4
O: -2 (-8)
H: +1 (+2)
S: +6
Mg is 0
In MgSO4
Mg: +2
S: +6
O: -2 (-8)
H2 is 0
O: -2 (-8)
H: +1 (+2)
S: +6
Mg is 0
In MgSO4
Mg: +2
S: +6
O: -2 (-8)
H2 is 0
why is the OXYGEN VALUE WRONG?
Have you written the correct equation on your post? There's no Sr or N in that forumula.
Original post by WinterDucky
In H2SO4
O: -2 (-8)
H: +1 (+2)
S: +6
Mg is 0
In MgSO4
Mg: +2
S: +6
O: -2 (-8)
H2 is 0
O: -2 (-8)
H: +1 (+2)
S: +6
Mg is 0
In MgSO4
Mg: +2
S: +6
O: -2 (-8)
H2 is 0
I copied the wrong question.
2Sr(NO3)2(s) → 2SrO(s) + 4NO2(g) + O2(g)
For the Sr(NO3)2:
Sr: +2
N: +5 (+10)
O: -2 (-12)
Sr: +2
N: +5 (+10)
O: -2 (-12)
Original post by WinterDucky
For the Sr(NO3)2:
Sr: +2
N: +5 (+10)
O: -2 (-12)
Sr: +2
N: +5 (+10)
O: -2 (-12)
why is the O -2 though, i got -6 for that.
Original post by Me123456789
why is the O -2 though, i got -6 for that.
Oxygen is always -2 unless it's in a peroxide.
Think about it... if the oxidation number of oxygen was -6 here then the overall charge of the molecule would be -24 which it is clearly not.
(edited 8 years ago)
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