The function f is defined as f(x) = 3 + lnx where x > 0
Another function, g is defined for all x as g(x) = ex4
Show that fg(x) = 4(1+ lnx)
So I've got up to fg(x) = e(3+ lnx)4, but no idea where to go from here to prove the above.
Would appreciate any support!
remember fg(x) == f(g(x)) = 3 + ln(ex^4). apply the rule log(ab) = log(a) + log(b). also apply the rule log(a^2) = 2log(a) remember, if you apply a function to its inverse, everything cancels out.
The function f is defined as f(x) = 3 + lnx where x > 0
Another function, g is defined for all x as g(x) = ex4
Show that fg(x) = 4(1+ lnx)
So I've got up to fg(x) = e(3+ lnx)4, but no idea where to go from here to prove the above.
Would appreciate any support!
I may be mistaken, but I think you substituted f(x) for x into g(x) instead of g(x) for x into f(x) From there, you can use log laws to get what they're looking for
I may be mistaken, but I think you substituted f(x) for x into g(x) instead of g(x) for x into f(x) From there, you can use log laws to get what they're looking for
I may be mistaken, but I think you substituted f(x) for x into g(x) instead of g(x) for x into f(x) From there, you can use log laws to get what they're looking for
Hang on, I still don't seem to be getting the same answer: