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Buffers :(

Hi guys I need help understanding buffers made from a weak acid and a salt. In my book it says to make up this buffer you need a large "reservoir" of the weak acid and salt (conjugate base) to stop any substantial change in pH. I really dont understand why you need a large reservoir.
Reply 1
Because a small reservoir would be less effective.

When you add an acid/alkali, you need a large amount of HA or A- to react with the added OH-/H+ so that the [H+] doesn't change by much and the pH change is resisted.

Imagine if you had a load of HA, but only a little bit of A-. If you added some OH-, then more HA could dissociate and replace the H+ lost and the pH wouldn't change by much. BUT, if you added some H+, there is only so much A- that could react (making HA) and the [H+] would increase and pH would drop quickly.
Original post by medicmadness
Hi guys I need help understanding buffers made from a weak acid and a salt. In my book it says to make up this buffer you need a large "reservoir" of the weak acid and salt (conjugate base) to stop any substantial change in pH. I really dont understand why you need a large reservoir.


Here is an interactive on buffers that may help you to understand the concepts
Reply 3
Original post by Pigster
Because a small reservoir would be less effective.

When you add an acid/alkali, you need a large amount of HA or A- to react with the added OH-/H+ so that the [H+] doesn't change by much and the pH change is resisted.

Imagine if you had a load of HA, but only a little bit of A-. If you added some OH-, then more HA could dissociate and replace the H+ lost and the pH wouldn't change by much. BUT, if you added some H+, there is only so much A- that could react (making HA) and the [H+] would increase and pH would drop quickly.


Doesnt the OH- react with the HA so how can H+ be lost?
Reply 4
HA <-> H+ + A-

You can consider the OH- reacting with the H+, lowering [H+]. OR you can consider the OH- reacting with the HA, then the Le C.P. says the equilibrium will go to the LHS, lowering [H+]
Reply 5
Original post by Pigster
HA <-> H+ + A-

You can consider the OH- reacting with the H+, lowering [H+]. OR you can consider the OH- reacting with the HA, then the Le C.P. says the equilibrium will go to the LHS, lowering [H+]


So about what you were saying earlier, if you didnt have much A- then this means not all the H+ added would be removed and so any of the unreacted H+ is what will cause a decrease in pH
Reply 6
Agreed.

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