Differentiation Help

Given that y=4x^3 - 5/2x^2 where x is not = to 0

Find dy/dx in simplest form

Find fydx (the f is meant to be integration sign i think)
Not sure where to start or what to do really so help will be great!

Reply 1

Kevin De Bruyne

21

Original post by Frstu

Given that y=4x^3 - 5/2x^2 where x is not = to 0

Find dy/dx in simplest form

Find fydx (the f is meant to be integration sign i think)
Not sure where to start or what to do really so help will be great!

Please post a picture of the question if you can :smile:

I'm not sure what you mean by that second bit.

How have you tried to find dy/dx?

Reply 2

Slowbro93

20

Original post by Frstu

Given that y=4x^3 - 5/2x^2 where x is not = to 0

Find dy/dx in simplest form

Find fydx (the f is meant to be integration sign i think)
Not sure where to start or what to do really so help will be great!

I'm assuming we have:

y=4x^{3} - \dfrac {5}{2x^{2}}

If so, the second part of the equation (the part with the fraction), have you converted it into index form so that you can manipulate it easier? And what are the rules of differentiation and integration?