CfE Higher Physics

Original post by Zrehman24

. How is your revision going? How many hours are you doing each day? Are you back to school

My revision is going ok- some days I do really well and other days I do not...I do about 8 hours on a good day, but the average is probably nearer 6 hours... I am still on Easter holiday- I go back next Tuesday. English is probably my biggest worry, but only because I hate it! How is your revision going and how long do you spend revising? When do you go back to school?(or are you back already?)

Reply 63

JP298

Original post by Zrehman24

. How is your revision going? How many hours are you doing each day? Are you back to school

For Maths and Physics the BEST thing you can do is past papers, work through them one by one.

Posted from TSR Mobile

Reply 64

Original post by JP298

For Maths and Physics the BEST thing you can do is past papers, work through them one by one.

Posted from TSR Mobile

I 100% agree with this.

Reply 65

Zrehman24

I'm back at school now but when I come back I revise a lot. Today I'm very tired so only managed to do physics today and go over refraction if light. I am trying to do as many past papers for maths and physics working my way through them and doing the questions I find challenging/ difficult. Hopefully with hard work and determination I'll achieve my goal

Reply 66

Hey guys, thanks so much that makes much more sense.

Still one or two questions though:

For q23, to get your answer you would have to draw a normal vertically. I thought the normal was displayed already in the diagram vertically???

And for q22, for maxima you use m=1 at each bright spot so a minima is therefore m=1/2 or m=1 and a 1/2 ??????????

And lastly @Labrador99, there is no way you're sitting the higher exam!?!?!?! You're amazing at Physics!!!!!!!!!! :smile:

You seriously helped me thanks so much. I hope I can get my 5A's this year and I too am worried so much about English because I hate it.

TSR is so good for help because people like you and asklepios don't get pissed when someone as stupid as me doesn't understand anything ahahaha. It's a nice change. :smile:

Thanks so much both of you guys :smile:

Reply 67

Anybody feeling generous?

Want to help Jeff over here on questions 3,7,13,21,23,27???

Would appreciate:
http://mrmackenzie.wikispaces.com/file/view/1994_HigherI.pdf

Reply 68

Original post by Jeff548

Anybody feeling generous?

Want to help Jeff over here on questions 3,7,13,21,23,27???

Would appreciate:
http://mrmackenzie.wikispaces.com/file/view/1994_HigherI.pdf

Hi Jeff548
Would you like hints or worked solutions?

Reply 69

Original post by Labrador99

Hi Jeff548
Would you like hints or worked solutions?

Worked solutions please if you could?

How are you so good at physics!?!?!!

Reply 70

Original post by Jeff548

Thanks so much both of you guys :smile:

For Q23- I'm not really sure what you're asking, but the normal is always drawn perpendicular to the boundary- so in this case, the boundary between the water and the air is horizontal across the page, therefore, the normal would be drawn in the vertical position. If this still doesn't help, I could draw a diagram if you want?

And for Q22- I was taught that for the equations on the relationship sheet to work...the maximum in the middle(at the dotted line) is the zero order maximum(m=0). The first minima that you reach above and below it are the zero order minima(again, m=0). The next maximum is the first order maximum(m=1) and R and S both show first order minima(m=1)... The way that maxima and minima are differentiated between is that the formulae used for each is slightly different...
For a maxima... Path difference = m x wavelength
For a minima... Path difference = (m + 1/2) x wavelength
I know some teachers have different preferred methods for doing this as my teacher likes us to use logic, but I prefer the formula, so if I have confused you further, apologies!

Thank you so much for your kind words...I genuinely hope that you do well and get the grades you want.
Glad to be of assistance :smile:

Reply 71

Original post by Labrador99

Cheers, got it.

So for first order maxima m=1 and for first order minima m=1 also? or for first order minima m=1/2?

I get the maxima just not the minima.

Reply 72

Original post by Jeff548

Worked solutions please if you could?

How are you so good at physics!?!?!!

Sure, coming up...I will post them as I do them :smile:

I'm ok at the calculations, but I am really bad at the explaining questions! I would say lots of practice questions, write down what you know from the question to help you decide what it is asking, don't miss any questions out and have a read at the specification and examiners report from last year's paper(both on the SQA website)- In fact, that's probably relevant for most, if not all subjects. :smile:

Reply 73

Original post by Jeff548

Cheers, got it.

So for first order maxima m=1 and for first order minima m=1 also? or for first order minima m=1/2?

I get the maxima just not the minima.

Hope this helps :smile:

Reply 74

Original post by Jeff548

Anybody feeling generous?

Want to help Jeff over here on questions 3,7,13,21,23,27???

Would appreciate:
http://mrmackenzie.wikispaces.com/file/view/1994_HigherI.pdf

Jeff548 I’ll put a hint so that you can try it yourself- you will benefit more if you figure it out for yourself (thanks Asklepios)…And then I’ll put the full worked solution in the spoiler if that’s ok?
Q3
s =50
u = 30
v = 0(because the car comes to rest)
a = ?
t =
Use v^2 = u^2 + 2as

Spoiler

Reply 75

Original post by Jeff548

Anybody feeling generous?

Want to help Jeff over here on questions 3,7,13,21,23,27???

Would appreciate:
http://mrmackenzie.wikispaces.com/file/view/1994_HigherI.pdf

Q7
Impulse = Ft

Spoiler

Here's the full answer...

Spoiler

Reply 76

[QUOTE="Jeff548;64147197"]Anybody feeling generous?

Want to help Jeff over here on questions 3,7,13,21,23,27???

Would appreciate:
http://mrmackenzie.wikispaces.com/file/view/1994_HigherI.pdf[/QUOTE]

Hope this helps :smile:

Q13
Hint: You will need to use the three equations V = IR, 1/R_T= 1/R₁ + 1/R₂ and R_T= R₁ + R₂ (in that order).

Spoiler

Here's the full answer:

Spoiler

Reply 77

Original post by Jeff548

Anybody feeling generous?

Want to help Jeff over here on questions 3,7,13,21,23,27???

Would appreciate:
http://mrmackenzie.wikispaces.com/file/view/1994_HigherI.pdf

Q21- This isn't the best explanation, so if anyone else has a better way of thinking, please share...
The light bends away from the normal when it travels from 1 to 2.
When light bends away from the normal, that means that it has travelled from a medium of high refractive index to a medium of low refractive index. Looking at the data sheet, this means that 1 might(for purposes of explanation/thinking) be glass and 2 might be air (as glass has a greater refractive index than air). Thinking about this, it make sense that the light would travel slower in glass than in air, hence v1<v2.

Spoiler

Reply 78

Original post by Jeff548

Anybody feeling generous?

Want to help Jeff over here on questions 3,7,13,21,23,27???

Would appreciate:
http://mrmackenzie.wikispaces.com/file/view/1994_HigherI.pdf

Q 23
To find out what happens as the ray enters the glass…When a ray of light travels from a medium with a lower refractive index to one with a higher refractive index, it bends towards the normal line. Eliminate the answers that don’t fit this rule.
To find out what happens at the second boundary…Find the angle of incidence at the second boundary. Compare with the critical angle (which you will need to calculate) and make a conclusion from this.
Full working in the spoiler….Hope this helps :smile:

Spoiler

(edited 8 years ago)

Reply 79