Original post by white_o
If you have 50cm^3 of 1 mol dm^-3 acid, HA and 0.119 moles of MgCO3 and the equation is 2HA + MgCO3 ---> MgA2 + H2O + CO2
How many moles of HA have reacted with MgCO3? Would it be 50*1/1000 = 0.05mol then /2 because of the molar ratio things in the equation, so 0.025? Thanks!
How many moles of HA have reacted with MgCO3? Would it be 50*1/1000 = 0.05mol then /2 because of the molar ratio things in the equation, so 0.025? Thanks!
0.05
All the HA will react as the magnesium carbonate is in excess. However only half of 0.05 of will react.
(edited 8 years ago)
Original post by keromedic
0.05
All the HA will react as the magnesium carbonate is in excess. However only half of 0.05 of will react.
All the HA will react as the magnesium carbonate is in excess. However only half of 0.05 of will react.
Ohhh okay, thanks!
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