PHYA4 simple harmonic motion question
http://filestore.aqa.org.uk/subjects/AQA-PHYA4-2-QP-JUN13.PDF
Question 1) b) ii)
You're asked to calculate the acceleration.
They appear to use the formula a = (2 x pi x f)^2 x A
but isn't this formula supposed to be the maximum acceleration? how do you know that it is the maximum?
Question 1) b) ii)
You're asked to calculate the acceleration.
They appear to use the formula a = (2 x pi x f)^2 x A
but isn't this formula supposed to be the maximum acceleration? how do you know that it is the maximum?
a=-(2πf)2x
x is the displacement from the equilibrium point
for a given pendulum in SHM the acceleration is always the same at displacement x whatever the amplitude of the oscillation... because the condition for SHM is a restoring force proportional to displacement (but opposite in direction)
x is the displacement from the equilibrium point
for a given pendulum in SHM the acceleration is always the same at displacement x whatever the amplitude of the oscillation... because the condition for SHM is a restoring force proportional to displacement (but opposite in direction)
(edited 8 years ago)
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