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mass spec question

I dont know how to do question 3, could anyone explain how to do this please?
FullSizeRender.jpg510.1KB
Reply 1
Avatar for Pigster
Pigster
20
There are eight possible combinations:

79 79 35
79 79 37
79 81 35
79 81 37
81 79 35
81 79 37
81 81 35
81 81 37

Work out the chances of each one and compile into a spectrum.
Original post by Pigster
There are eight possible combinations:

79 79 35
79 79 37
79 81 35
79 81 37
81 79 35
81 79 37
81 81 35
81 81 37

Work out the chances of each one and compile into a spectrum.


There are only 6 possible molecules.

81 79 is the same as 79 81, as in its the same combination but with double the probability (as I'm sure you know)
Reply 3
Avatar for Pigster
Pigster
20
They could be structural isomers.
Reply 4
Avatar for jacksonmeg
jacksonmeg
OP
11
Original post by Pigster
There are eight possible combinations:

79 79 35
79 79 37
79 81 35
79 81 37
81 79 35
81 79 37
81 81 35
81 81 37

Work out the chances of each one and compile into a spectrum.


so the height is the probability? but what am i actually plotting on the bottom?
Original post by jacksonmeg
so the height is the probability? but what am i actually plotting on the bottom?


m/z
Reply 6
Avatar for Pigster
Pigster
20
Yes and m/z or m/e whichever is preferred, I'd go with some random (large-ish) number, n, and go up to n+5.

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