How do I integrate this? c4

-2ln1+x^2 is what I thought but that's wrong

Posted from TSR Mobile

Original post by Lilly1234567890

-2ln1+x^2 is what I thought but that's wrong

Posted from TSR Mobile

\displaystyle \int -2 (1+x)^{-2} \, \mathrm{d}x

(add one to the power and divide by the new power, remember that...?)

Logarithmic terms only appear if you have 1/x and not 1/x^2.

\displaystyle \int -2 (1+x)^{-2} \, \mathrm{d}x

(add one to the power and divide by the new power, remember that...?)

Logarithmic terms only appear if you have 1/x and not 1/x^2.

Original post by Lilly1234567890

-2ln1+x^2 is what I thought but that's wrong

Posted from TSR Mobile

ermmm it's the wrong way up :s-smilie:

Original post by Lilly1234567890

Do you understand your mistake? A sub u = x+1 may make things clearer.

ermmm it's the wrong way up :s-smilie:

I had to crane my neck. :lol:

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