1. The centre of the circle has coordinates (3, -2)
You now have two sets of coordinates. Using these; (3, -2) & (-2, 8); find the gradient of the line connecting these two points. Then, you can work out the gradient of the tangent (negative reciprocal), which is perpendicular to that line.
Using y=mx+c, substitute your coordinates in and the gradient to find the value of C. And you have your equation of the tangent!
2. Remember... When a line, curve or circle crosses the x axis, y is equal to 0. So substitute y=0 and work out the values of x from there.
3. It's simultaneous equations. You know at the points where the lines meet they both equal one another.
The best way to go about this is by substitution.
Replace all the y values in your circle equation with x+4; because y=x+4.
The details should be trivial. If they aren't, make sure you
check with your teacher ASAP for help!