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Mechanics questions

Can someone please help me solve this?

Q) Eletrons in a particle accelerator are moving at 8.0x10^5ms-1 when they enter a tube where they accelerated to 6.5x10^6 ms-1
a)What is their acceleration in the tube?
b)What is the length of the tube?

Q)A high speed train can slow down smoothly from a speed of 190kmh^-1 to rest within a distance of 1500m.
a)What is the average speed of the train, in, ms^-1, as it slows down?

These kind of questions really annoy me
Original post by CookieHero
Can someone please help me solve this?

Q) Eletrons in a particle accelerator are moving at 8.0x10^5ms-1 when they enter a tube where they accelerated to 6.5x10^6 ms-1
a)What is their acceleration in the tube?
b)What is the length of the tube?

Q)A high speed train can slow down smoothly from a speed of 190kmh^-1 to rest within a distance of 1500m.
a)What is the average speed of the train, in, ms^-1, as it slows down?

These kind of questions really annoy me


Appears to be some information missing in the first question...
is it related to Q 1.26 here http://www.hatchend.harrow.sch.uk/_files/Sixth%20Form/00336966246BBA1ADEF307A8547A142C.pdf
Reply 2
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CookieHero
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Original post by Joinedup
Appears to be some information missing in the first question...
is it related to Q 1.26 here http://www.hatchend.harrow.sch.uk/_files/Sixth%20Form/00336966246BBA1ADEF307A8547A142C.pdf


I do have the book and yes it is Q 1.26. In the back of the book it says the answer is 9.0 x 10^12 ms^-2 for quesiton 1.26a

I'm guessing there are actually missing information in the questions.
(edited 8 years ago)
Original post by CookieHero
Can someone please help me solve this?

Q) Eletrons in a particle accelerator are moving at 8.0x10^5ms-1 when they enter a tube where they accelerated to 6.5x10^6 ms-1
a)What is their acceleration in the tube?
b)What is the length of the tube?

Q)A high speed train can slow down smoothly from a speed of 190kmh^-1 to rest within a distance of 1500m.
a)What is the average speed of the train, in, ms^-1, as it slows down?

These kind of questions really annoy me


did it say how long the electrons were in the tube for ?
Reply 4
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CookieHero
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Original post by the bear
did it say how long the electrons were in the tube for ?


nope D:
Original post by CookieHero
nope D:


perhaps they mentioned the kinetic energy of the electrons ?
Reply 6
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Kyx
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Original post by CookieHero
Can someone please help me solve this?

Q) Eletrons in a particle accelerator are moving at 8.0x10^5ms-1 when they enter a tube where they accelerated to 6.5x10^6 ms-1
a)What is their acceleration in the tube?
b)What is the length of the tube?

Q)A high speed train can slow down smoothly from a speed of 190kmh^-1 to rest within a distance of 1500m.
a)What is the average speed of the train, in, ms^-1, as it slows down?

These kind of questions really annoy me


Q1a) a = v - u (final velocity minus initial velocity)

Q1b) using v = u + at, you can solve for time.

then we can use s = ut +1/2 at^2 to get the length of the tube.

Q2a) Average speed = (v + u)/2 or the two velocities added together and divided by two.
Reply 7
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Kyx
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Original post by the bear
did it say how long the electrons were in the tube for ?


Original post by the bear
perhaps they mentioned the kinetic energy of the electrons ?



Please see my above post.
Original post by CookieHero
nope D:


Using just the info you provided, it is not possible to solve the first question but using the info in the link provided by one of the other posters it should be easy as you're given the time, initial and final velocity
Original post by Kyx
Q1a) a = v - u (final velocity minus initial velocity)

Q1b) using v = u + at, you can solve for time.

then we can use s = ut +1/2 at^2 to get the length of the tube.

Q2a) Average speed = (v + u)/2 or the two velocities added together and divided by two.


acceleration doesnt = v-u

v-u just gives the change in velocity

a= (v-u)/t
(edited 8 years ago)
Original post by Kyx
Please see my above post.


as i suspected there was some extra information to enable the use of SUVAT equations.
Reply 11
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Kyx
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Original post by madmadmax321
acceleration doesnt = v-u

v-u just gives the change in velocity

a= (v-u)/t


Of course!
Reply 12
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CookieHero
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I get it now thanks
Reply 13
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Kyx
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Original post by CookieHero
I get it now thanks


What was it? :smile:
Reply 14
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CookieHero
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Original post by Kyx
What was it? :smile:


wut was what? :?
Reply 15
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Kyx
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Original post by CookieHero
wut was what? :?


The answer?

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